URI Online Judge Solution 1115 || Quadrant

URI Online Judge | 1115

Quadrant

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Write a program to read the coordinates (X, Y) of an indeterminate number of points in Cartesian system. For each point write the quadrant to which it belongs. The program finish when at least one of two coordinates is NULL (in this situation without writing any message).

Input

The input contains several tests cases. Each test case contains two integer numbers.

Output

For each test case, print the corresponding quadrant which these coordinates belong, as in the example.

Input Sample	Output Sample
2 2 3 -2 -8 -1 -7 1 0 2	primeiro quarto terceiro segundo

Adjustments and translating by Cássio Favaretto.

URI Online Judge Solution  1115 || Quadrant in C

#include <stdio.h>

int main()
{
    int x;
    int y;

    scanf("%d", &x);
    scanf("%d", &y);

    if(x == 0 || y == 0){
            return 0;
    }

    while(x != 0 || y != 0){

        if(x > 0 && y > 0){
            printf("primeiro\n");
        }
        if(x < 0 && y > 0){
            printf("segundo\n");
        }
        if(x < 0 && y < 0){
            printf("terceiro\n");
        }
        if(x > 0 && y < 0){
            printf("quarto\n");
        }

        scanf("%d", &x);
        scanf("%d", &y);

        if(x == 0 || y == 0){
            return 0;
        }
    }

    return 0;
}

URI Online Judge Solution  1115 || Quadrant in JAVA

import java.io.IOException;

import java.util.Scanner;

 

public class Main {

 

    public static void main(String[] args) throws IOException {

        int firstsign, secondSign;

        Scanner input = new Scanner(System.in);

        while (((firstsign = input.nextInt()) != 0)

                && ((secondSign = input.nextInt()) != 0)) {

            if (firstsign > 0 && secondSign > 0) {

                System.out.print("primeiro\n");

            } else if (firstsign > 0 && secondSign < 0) {

                System.out.print("quarto\n");

            } else if (firstsign < 0 && secondSign < 0) {

                System.out.print("terceiro\n");

            } else if (firstsign < 0 && secondSign > 0) {

                System.out.print("segundo\n");

            }

        }

    }

}

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