URI Solution 1006 in C, C++ and Java language (URI online Judge)

Main Link :  https://www.urionlinejudge.com.br/judge/en/problems/view/1006

URI Online Judge | 1006

Average 2

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read three values (variables A, B and C), which are the three student's grades. Then, calculate the average, considering that grade A has weight 2, grade B has weight 3 and the grade C has weight 5. Consider that each grade can go from 0 to 10.0, always with one decimal place.

Input

The input file contains 3 values of floating points with one digit after the decimal point.

Output

Print MEDIA(average in Portuguese) according to the following example, with a blank space before and after the equal signal.

Input Samples	Output Samples
5.0 6.0 7.0	MEDIA = 6.3

5.0 10.0 10.0

MEDIA = 9.0

10.0 10.0 5.0

MEDIA = 7.5

Solution in C language:

---

#include <stdio.h>
int main()
{
double a, b, c, media;
scanf("%lf%lf%lf", &a, &b, &c);
media = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
printf("MEDIA = %.1lf\n", media);
return 0;
}

Solution in C++ language:

---

#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
double a, b, c, media;
cin >> a >> b >> c;
media = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);
cout << "MEDIA = "<< fixed << setprecision(1) << media << endl;
return 0;
}

Solution in Java language:

---

package uri_java_problem_solution;


import java.util.Scanner;

public class URI_1006 {

    public static void main(String[] args){

        double a, b, c, med;

        Scanner sc =new Scanner(System.in);

           a =sc.nextDouble();

           b =sc.nextDouble();

           c =sc.nextDouble();

         med = (a/10 * 2) + (b/10 * 3) + (c/10 * 5);



        String media = String.format("MEDIA = %,.1f", med);

        System.out.print(media +"\n");

    }
}