URI Online Judge Solution 1116 || Dividing X by Y

URI Online Judge | 1116

Dividing X by Y

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 2

Write a program that read two numbers X and Y and print the result of dividing the X by Y. If it's not possible, print the message "divisão impossível".

Input

The input contains an integer number N. This N is the quantity of pairs of integer numbers X and Y read (dividend and divisor).

Output

For each test case print the result of this division with one digit after the decimal point, or “divisão impossível” if it isn't possible to perform the calculation.

Obs.: Be carefull. The division between two integers in some languages generates another integer. Use cast:)

Input Sample	Output Sample
3 3 -2 -8 0 0 8	-1.5 divisao impossivel 0.0

Adjustments and translation by Cássio Favaretto.

URI Online Judge Solution 1116  ||  Dividing X by Y in JAVA

import java.io.IOException;

import java.util.Scanner;

 

public class Main {

 

    public static void main(String[] args) throws IOException {

        int N;

        int X, Y;

        float result;

        Scanner input =new Scanner(System.in);

        N = input.nextInt();

        for (int i = 1; i <= N; i++) {

            X = input.nextInt();

            Y = input.nextInt();

                if (Y == 0) {

                    System.out.print("divisao impossivel\n");

                }else {

                    result =(float) X / Y;

                    System.out.printf("%.1f\n",result);

                }

                 

        }

    }

}

URI Online Judge Solution 1116  ||  Dividing X by Y in C++

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
        int n;
        float x, y;

        cin >> n;

        for(int i = 0; i < n; ++i)
        {
            cin >> x >> y;

            if(y == 0){
                cout << "divisao impossivel" << endl;
            }else{
                cout << fixed << setprecision(1) << (x/y) << endl;
            }
        }

        return 0;
}

URI Online Judge Solution 1116  ||  Dividing X by Y in C

#include <stdio.h>

int main()
{
        int n, i;
        float x, y;

        scanf("%d", &n);

        for(i = 0; i < n; ++i)
        {
            scanf("%d%d", &x, &y);

            if(y == 0){
                printf("divisao impossivel\n");
            }else{
                printf("%.1f\n",  (x/y) );
            }
        }

        return 0;
}

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