URI Solution 1087 - Queen - Solution in C++ | Ad Hoc

URI Solution 1087 - Queen - Solution in C++ | Ad Hoc

URI Online Judge Solution  | Ad Hoc


Problem Name: URI Problem - Queen
Problem Number : URI - 1087
Online Judge : URI Online Judge Solution
Level: Ad Hoc
Solution Language : C plus plus

URI Solution 1087 Code in CPP:

#include <cstdio>
#include <cmath>

using namespace std;

int abss(int a) {
 return a < 0 ? -a : a;
}

int main()
{
 int X1, Y1, X2, Y2 = 0;
 int res, res2 =0;
 
 scanf("%d", &X1);
 scanf("%d", &Y1);
 scanf("%d", &X2);
 scanf("%d", &Y2);
 
 
 while(X1 != 0 && Y1 != 0 && X2 != 0 && Y2 != 0)
 {
  if(X1 == X2 && Y1 == Y2)
  {
   printf("0\n");
  }else if(X1 == X2 || Y1 == Y2)
  {
   printf("1\n");
  }else
  {
   res = abss(X1 - X2);
   res2 = abss(Y1 - Y2);
  
   if(res - res2 == 0)
   {
    printf("1\n");
   }else
   {
    printf("2\n");
   }
  }
  
 
  scanf("%d", &X1);
  scanf("%d", &Y1);
  scanf("%d", &X2);
  scanf("%d", &Y2);
 }
 return 0;
}