URI Online Judge Solution 1133 || Rest of a Division

URI Online Judge | 1133

Rest of a Division

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Write a program that reads two integer numbers X and Y. Print all numbers between X and Y which dividing it by 5 the rest is equal to 2 or equal to 3.

Input

The input file contains 2 integer numbers X and Y without any order.

Output

Print all numbers according to above description, always in ascending order.

Input Sample	Output Sample
10 18	12 13 17

URI Online Judge Solution 1133 || Rest of a Division in C Language

#include<stdio.h>
int main(){
    int X, Y, i;
    scanf("%d%d", &X,&Y);
    if (X > Y) {
         for (i = Y+1 ; i < X; i++) {
                if (i % 5 == 2 || i % 5 == 3) {
                    printf("%d\n", i);
                }
            }
    }else if(X < Y){
        for (i = X+1 ; i < Y; i++) {
                if (i % 5 == 2 || i % 5 == 3) {
                     printf("%d\n", i);
                }
            }
    }

}

URI Online Judge Solution 1133 || Rest of a Division in Java Language

import java.io.IOException;

import java.util.Scanner;

public class Main {

    public static void main(String[] args) throws IOException {

        int X, Y;

        Scanner input =new Scanner(System.in);

        X = input.nextInt();

        Y = input.nextInt();

         

        if (X > Y) {

             

            for (int i = Y+1 ; i < X; i++) {

                if (i % 5 == 2 || i % 5 == 3) {

                    System.out.print(i+"\n");

                }

            }

        }else if(Y > X){

            for (int i = X+1 ; i < Y; i++) {

                if (i % 5 == 2 || i % 5 == 3) {

                    System.out.print(i+"\n");

                }

            }

        }

    }

}

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