URI Solution 1073 in C, C++ and Java language

URI Online Judge | 1073

Even Square

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read an integer N. Print the square of each one of the even values from 1 to N including N if it is the case.

Input

The input contains an integer N (5 < N < 2000).

Output

Print the square of each one of the even values from 1 to N, as the given example.

Be carefull! Some language automaticly print 1e+006 instead 1000000. Please configure your program to print the correct format setting the output precision.

Input Sample	Output Sample
6	2^2 = 4 4^2 = 16 6^2 = 36

Solution 1073 in Java language:

import java.util.Scanner;


public class URI_1072 {


 public static void main(String[] args) {
  int N , X, in = 0, out = 0;
  int interval_start =10,interval_end =20 ;
  
  Scanner input =new Scanner(System.in);
  
  N =input.nextInt();
  for (int i = 1; i <= N; i++) {
   X =input.nextInt();
   if (X >= interval_start && X <= interval_end) {
    in += 1;
   }else {
    out += 1;
   }
  }
  System.out.print(in+" in\n"+out +" out\n");
  


 }


}




URI Solution 1073 in C

1. #include <stdio.h>
2. int main()
3. {
4. int n, i;
5. 
   
6. scanf("%d", &n);
7. 
   
8. for ( i = 1; i <= n; ++i)
9. {
10. if(i % 2 == 0){
11. printf("%d^2 = %d\n", i,(i * i));
12. }
13. }
14. 
    
15. return 0;
16. }

URI Solution 1073 in C++

1. #include <iostream>
2. 
   
3. using namespace std;
4. 
   
5. int main()
6. {
7. int n;
8. 
   
9. cin >> n;
10. 
    
11. for (int i = 1; i <= n; ++i)
12. {
13. if(i % 2 == 0){
14. cout << i << "^2 = " << (i * i) << endl;
15. }
16. }
17. 
    
18. return 0;
19. }