URI 1043 Solution in java language || Triangle

View the main link :
https://www.urionlinejudge.com.br/judge/en/problems/view/1043

URI Online Judge | 1043

Triangle

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read three point floating values (A, B and C) and verify if is possible to make a triangle with them. If it is possible, calculate the perimeter of the triangle and print the message:

Perimetro = XX.X

If it is not possible, calculate the area of the trapezium which basis A and B and C as height, and print the message:

Area = XX.X

Input

The input file has tree floating point numbers.

Output

Print the result with one digit after the decimal point.

Input Sample	Output Sample
6.0 4.0 2.0	Area = 10.0

6.0 4.0 2.1

Perimetro = 12.1

URI 1043 Solution in Java language:

package URI_Problems_solution;

/**

    6.0 4.0 2.0 Area = 10.0

    6.0 4.0 2.1 Perimetro = 12.1



 */

import java.util.Scanner;



public class URI_1043 {



 public static void main(String[] args) {

  float A, B, C, areaTraphisium, perimeterTriangle ;

  

  Scanner input =new Scanner(System.in);

  A = input.nextFloat();

  B = input.nextFloat();

  C = input.nextFloat();

  

  if ((A < (float)(B+C)) && (B < (float)(A+C)) && (C < (float)(B+A))) {

   //Triangle perimeter = a + b + c;

   //Traphisium area is = (a + b)*h/2

   perimeterTriangle = A + B + C;

   System.out.printf("Perimetro = %.1f\n",perimeterTriangle);

  

   

  }else {

   areaTraphisium = ((A + B) * C) / 2;

   System.out.printf("Area = %.1f\n",areaTraphisium);

   }

 }



}